{"id":2899,"date":"2023-02-15T14:11:18","date_gmt":"2023-02-15T11:11:18","guid":{"rendered":"https:\/\/kucukelmakurdu.com\/gule-gule-exynos-galaxy-s23-serisi-dunya-capinda-snapdragon-8-gen-2yi-kullaniyor-ve-bu-qualcomm-ve-samsung-icin-bir-kazan-kazan-durumu\/"},"modified":"2023-02-15T14:11:18","modified_gmt":"2023-02-15T11:11:18","slug":"gule-gule-exynos-galaxy-s23-serisi-dunya-capinda-snapdragon-8-gen-2yi-kullaniyor-ve-bu-qualcomm-ve-samsung-icin-bir-kazan-kazan-durumu","status":"publish","type":"post","link":"https:\/\/kucukelmakurdu.com\/gule-gule-exynos-galaxy-s23-serisi-dunya-capinda-snapdragon-8-gen-2yi-kullaniyor-ve-bu-qualcomm-ve-samsung-icin-bir-kazan-kazan-durumu\/","title":{"rendered":"G\u00fcle g\u00fcle Exynos! Galaxy S23 serisi, d\u00fcnya \u00e7ap\u0131nda Snapdragon 8 Gen 2’yi kullan\u0131yor ve bu, Qualcomm ve Samsung i\u00e7in bir kazan-kazan durumu."},"content":{"rendered":"


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Galaxy S23 serisi resmiyet kazand\u0131 ve heyecanlanacak \u00e7ok \u015fey olmas\u0131na ra\u011fmen, Samsung bir kilit alanda i\u015fleri farkl\u0131 yap\u0131yor. Samsung, yakla\u015f\u0131k on y\u0131ld\u0131r ilk kez Qualcomm’un Snapdragon 8 Gen 2’sini d\u00fcnya \u00e7ap\u0131nda t\u00fcm Galaxy S23 modelleri i\u00e7in sunuyor ve Exynos varyant\u0131 sunulmuyor. Samsung bunu en son 2014’te Galaxy S5 ile yapm\u0131\u015ft\u0131, yani bu \u00e7ok \u00f6nemli bir olay.<\/p>\n

Samsung, son be\u015f y\u0131ld\u0131r ikili kaynak sa\u011flama stratejisine g\u00fcvendi; G\u00fcney Koreli \u00fcretici, Galaxy S serisinin Qualcomm destekli varyantlar\u0131n\u0131 Kuzey Amerika, Kore ve \u00c7in i\u00e7in kullan\u0131rken, di\u011fer b\u00f6lgelerde Exynos destekli versiyonlar\u0131n\u0131 piyasaya s\u00fcrd\u00fc. Ge\u00e7en y\u0131l Samsung, Galaxy S21’in Snapdragon 8 1. Nesil destekli s\u00fcr\u00fcm\u00fcn\u00fc Hindistan ve BAE gibi \u00f6nemli b\u00f6lgeler de dahil olmak \u00fczere daha fazla k\u00fcresel pazarda sunmaya ba\u015flad\u0131\u011f\u0131nda bu stratejide bir de\u011fi\u015fiklik g\u00f6r\u00fcld\u00fc.<\/p>\n